x^2-10x+26=(x^2+1)-5

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Solution for x^2-10x+26=(x^2+1)-5 equation: 



x^2-10x+26=(x^2+1)-5

We move all terms to the left:

x^2-10x+26-((x^2+1)-5)=0



We calculate terms in parentheses: -((x^2+1)-5), so:

(x^2+1)-5

We get rid of parentheses

x^2+1-5

We add all the numbers together, and all the variables

x^2-4

Back to the equation:

-(x^2-4)



We get rid of parentheses

x^2-x^2-10x+4+26=0

We add all the numbers together, and all the variables

-10x+30=0

We move all terms containing x to the left, all other terms to the right

-10x=-30

x=-30/-10

x=+3

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